Two sources of light emit X – rays of wavelength 1nm and visible light of wavelength 500nm, respectively. Both the sources emit light of the same power 200W. The ratio of the number density of photons of X – rays to the number density of photons of the visible light of the given wavelength is :

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1250

250

1500

500

answer is C.

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Detailed Solution

Power=P=nthcλ ⇒nt=Pλhc∴n1n2=λ1λ2⇒n1n2=1500

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