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The pressure and density of a diatomic gas γ=75  changes adiabatically from  (P,δ) to (P11) . If  δδ1=32, then P1P  is:

a
1128
b
128
c
32
d
none of these

detailed solution

Correct option is A

adiabatic relation between Pressure P and volume V is  PVγ=Constant---(1)density(δ) =mass(m) volume(V) ⇒V=mδ substitute in eqn(1)  mass is constant hence,Pδγ=ConstantP1(δγ)1=Pδγ  P1P=δ1δγ  substitute the given values ⇒P1P=1327/5 ⇒P1P=127 ⇒P1P=1128

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