The pressure and density of a diatomic gas γ=75 changes adiabatically from (P,δ) to (P1,δ1) . If δδ1=32, then P1P is:
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a
1128
b
128
c
32
d
none of these
answer is A.
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Detailed Solution
adiabatic relation between Pressure P and volume V is PVγ=Constant---(1)density(δ) =mass(m) volume(V) ⇒V=mδ substitute in eqn(1) mass is constant hence,Pδγ=ConstantP1(δγ)1=Pδγ P1P=δ1δγ substitute the given values ⇒P1P=1327/5 ⇒P1P=127 ⇒P1P=1128