Q.
A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure P1=105Pa and volume Vi=10−3m3 changes to final state at Pf=132×105pa&Vf=8×10−3m3in an adiabatic quasi-static process, such that P3V5= constant. Consider another thermodynamic process that brings the system form the same initial state to the same final state in two steps: an isobaric expansion at Pi followed by an isochoric (is volumetric) process at volumeVf. The amount of heat supplied to the system in the two-step process is approximately
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a
112 J
b
294 J
c
588 J
d
813 J
answer is C.
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Detailed Solution
For adiabatic processP3V5=consntPV5/3=consntr=5/3For process ACΔQ1=nCpΔT=n52RΔT =52PΔVΔQ1=17.5×102J=1750JFor process CDΔQ2=nCvΔT=n(32R)=32VΔPΔQ2=3/2×8×10−3×(−1+132)×105ΔQ2=−11.625×102ΔQnet=1750−1162=588J
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