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Q.

The pressure of a monoatomic gas increases linearly from 4×105 Pa to 8×105 Pa when its volume increases from 0.2 m3 to  0.5m3 then  increase in internal energy in  joule is

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a

4.8×105

b

4.8×104

c

6.8×104

d

2.4×105

answer is A.

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Detailed Solution

Change in internal energy of a gas is given by ∆U =nCvdT= nRγ-1T2-T1=P2V2-P1V1γ-1 As the gas is monoatomic, g = 5/3             So ∆U=1058×0.5-4×0.253-1=32×3.2×105=4.8×105
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