The pressure of a monoatomic gas increases linearly from 4×105 Pa to 8×105 Pa when its volume increases from 0.2 m3 to 0.5m3 then increase in internal energy in joule is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
4.8×105
b
4.8×104
c
6.8×104
d
2.4×105
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Change in internal energy of a gas is given by ∆U =nCvdT= nRγ-1T2-T1=P2V2-P1V1γ-1 As the gas is monoatomic, g = 5/3 So ∆U=1058×0.5-4×0.253-1=32×3.2×105=4.8×105