In a process the pressure of a gas is inversely proportional to the square of the volume. If the temperature of the gas increases, then work done by the gas
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a
is positive
b
is negative
c
is zero
d
may be positive
answer is B.
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Detailed Solution
Pα1V2⇒P=kV2⇒PV2=constPV.V=k⇒nRTV=k⇒TV=k1Since temperature increases therefore volume decreases. Hence the work done by the gas should be negative
In a process the pressure of a gas is inversely proportional to the square of the volume. If the temperature of the gas increases, then work done by the gas