First slide

Different type of processes

Question

In a process the pressure of a gas is inversely proportional to the square of the volume. If the temperature of the gas increases, then work done by the gas

Difficult

A

is positive
B

is negative
C

is zero
D

may be positive

Solution

$\begin{array}{l} P α \frac{1}{V^{2}} \Rightarrow P = \frac{k}{V^{2}} \Rightarrow P V^{2} = c o n s t \\ P V . V = k \Rightarrow n R T V = k \Rightarrow T V = k_{1} \end{array}$
Since temperature increases therefore volume decreases. Hence the work done by the gas should be negative

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App