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Q.

In a process the pressure of a gas is inversely proportional to the square of the volume. If the temperature of the gas increases, then work done by the gas

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a

is positive

b

is negative

c

is zero

d

may be positive

answer is B.

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Detailed Solution

Pα1V2⇒P=kV2⇒PV2=constPV.V=k⇒nRTV=k⇒TV=k1Since temperature increases therefore volume decreases. Hence the work done by the gas should be negative
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In a process the pressure of a gas is inversely proportional to the square of the volume. If the temperature of the gas increases, then work done by the gas