First slide

Calorie

Question

An ice block of mass 8 kg is dragged along a rough horizontal surface (=0.4) uniformly through 42 m. If all the heat produced is completely absorbed by block then mass of ice that melts is ( L= 80 cal/gm, g = 10m/s²)

Moderate

A

40 gm
B

4 kg
C

4gm
D

400 gm

Solution

work done against frictional force = heat produced for melting
$μMgs = JmL m is the mass of ice melt and L is the latent heat of fusion of ice 0.4 \times 8 \times 10 \times 42 = 4200 \times m \times 80 m = 4 \times 10^{- 3} kg = 4 gm$

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