P-T curve of a cyclic process is shown. If number of moles of the gas are n, the work done by the gas in the given process is
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a
nR(T1+T3-T4+T2)
b
nR(T1-T3-T4+T2)
c
nR(T1+T3+T4-T2)
d
nR(T1+T3-T4-T2)
answer is D.
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Detailed Solution
Since paths AB and CD are isochoric, therefore work done during AB and CD is zero. Paths BC and DA are isobaric.Hence WBC = nR∆T = nR(T3-T2) WDA = nR(T1-T4)Total work done = WBC+WDA = nR(T1+T3-T4-T2)