First slide

Work done by gas

Question

One mole of an ideal gas is heated at a constant pressure of 1 atm from 0⁰C to 100⁰ C. Work done by the gas is

Moderate

A

$8.31 \times 10^{3} J$
B

$8.31 \times 10^{- 3} J$
C

$8.312 \times 10^{- 3} J$
D

$8.31 \times 10^{2} J$

Solution

$d U = d Q - d W$
$\Rightarrow d W = d Q - d U$
For ideal gas, dU = 0
$\begin{aligned} ∴ d W = d Q = R (T_{2} - T_{1}) \\ = 831 \times 100 = 831 \times 10^{2} J \end{aligned}$

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