Questions
One mole of an ideal gas is heated at a constant pressure of 1 atm from 00C to 1000 C. Work done by the gas is
a
8.31×103J
b
8.31×10−3J
c
8.312×10−3J
d
8.31×102J
detailed solution
Correct option is D
dU=dQ−dW⇒dW=dQ−dUFor ideal gas, dU = 0∴ dW=dQ=RT2−T1=831×100=831×102JTalk to our academic expert!
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The equation of a state of a gas is given by (V b) = nRT. 1 mol of a gas is isothermally expanded from volume V to 2V, the work done during the process is
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