The ratio of the number of moles of a monoatomic to a polyatomic gas in a mixture of the two, behaving as an diatomic gas is : (vibrational modes of freedom is to be ignored)
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a
2 : 1
b
1 : 2
c
2 : 3
d
3 : 2
answer is B.
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Detailed Solution
Let the required ratio be n : 1Q1 = n(f1R2)∆T and Q2 = 1(f2R2)∆Tand Q = (n+1)(f2R∆T2) Q = Q1+Q2, So (n+1)f2 = nf1+f3or (n+1)5 = n(3) + 6 ⇒ n = 12