The ratio of specific heats of a gas is x. The change in internal energy of one mole of the gas, when the volume changes from V to 3V at constant pressure P is
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a
PVx
b
PV
c
2PV(x−1)
d
xPV(x−1)
answer is C.
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Detailed Solution
W=P(3V−V)=2PV initial temperature is T, final temperature T1=3T∴ΔU=1.CV.ΔT=R(x−1).(3T−T)=2RTx−1=2PV(x−1)[∵PV=1.RT]
The ratio of specific heats of a gas is x. The change in internal energy of one mole of the gas, when the volume changes from V to 3V at constant pressure P is