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Q.

A body of length 1 m having cross sectional area 0.75 m2 has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference if K = 200 Jm-1 K-1

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a

200C

b

400C

c

800C

d

1000C

answer is B.

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Detailed Solution

Qt = KA∆θl⇒ 6000 = 200×0.75×∆θ1∆θ = 6000×1200×0.75 = 400C

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