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A string of length 1m has the mass per unit length 0.1 gm/cm . Two ends of the string are attached to two rigid walls. A transverse vibration is set up in the string . A tension of 400 N is maintained in the string 2t the string oscillates in the first overtone and maximum displacement of a particle of the string is 2mm, the maximum velocity of a particle of the string is 

a
4.371 m/s
b
2.512 m/s
c
3.42 m/s
d
24.8 m/s

detailed solution

Correct option is B

2×λ2=l⇒λ=l=1mVelocity of wave, v=Tμ=40010−2m/s=200 m/s∴Frequency, f=vλ=2001Hz=200Hz∴Maximum particle velocity, umax=A×2πf=2×10−3×2π×200m/s                                                                                                                             =2.512m/s

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