The displacement y of a particle in a medium can be expressed as y=10−6sin100t+20x+x4 , wheret is in second and x in metre. The speed of the wave is
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a
2000 ms-1
b
5 ms-1
c
20 ms-1
d
5π ms-1
answer is B.
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Detailed Solution
The displacement is given by y=10−6sin100t+20x+π4Comparing with standard equation y=Asin(ωt+kx+ϕ)we get ω=100,k=20where, ω is angular frequency and k is angular wave number.Now, k=2πλ=2πvλv=ωv=20⇒ v=ω20=10020=5ms−1So, the speed of the wave is 5 ms-1.