First slide

Heat given

Question

The temperature of 5 moles of a gas at constant volume is changed from 100°C to 120°C. The change in internal energy is 80J. The total heat capacity of the gas at constant volume will be in joule/kelvin is

Easy

A

8
B

4
C

0.8
D

0.4

Solution

$\Delta T = \left( {120 - 100} \right)K = 20K$
${Q_V} = n{C_v}\Delta T$
$\therefore$ Heat capacity = nC_V
$= \frac{{{Q_V}}}{{\Delta T}}$
$= \frac{{80}}{{20}}J/K$
= 4 J/K

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