First slide

Change in internal energy

Question

In a thermodynamical process pressure of fixed mass of gas is changed in such a way that the gas molecules give out 30 J of heat and 10 J of work is done on the gas. If the internal energy of the gas was 40 J, the final internal energy will be:

Easy

A

zero
B

80 J
C

20 J
D

-20 J

Solution

dQ = du + dw
-30 = U $d Q = U_{2} - U_{1} + d w - 30 = U_{2} - 40 - 10 U_{2} = 20 J$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App