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A thermodynamical process is shown in with $P_{A}$ = 3 X 10⁴ Pa; $V_{A}$ = 2 X 10^-3 m³; $P_{B}$ = 8 x 10⁴ N/m²; $V_{D}$ = 5 x 10^-3 m³.In the processes AB and BC, 600 J and 200 J of heat is added to the system respectively. The change in internal energy of the system in process AC would be:

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560 J

800 J

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640 J

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detailed solution

Correct option is A

PBFor process A→B→C ;Q=W+∆U ⇒ ∆U=Q-W=600+200-(8×104)(5-2)×10-3 =800-240=560 J

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A thermodynamical process is shown in with PA= 3 X 104 Pa; VA = 2 X 10-3 m3; PB = 8 x 104 N/m2; VD = 5 x 10-3 m3.In the processes AB and BC, 600 J and 200 J of heat is added to the system respectively. The change in internal energy of the system in process AC would be:

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A thermodynamical process is shown in with $P_{A}$ = 3 X 10⁴ Pa; $V_{A}$ = 2 X 10^-3 m³; $P_{B}$ = 8 x 10⁴ N/m²; $V_{D}$ = 5 x 10^-3 m³.In the processes AB and BC, 600 J and 200 J of heat is added to the system respectively. The change in internal energy of the system in process AC would be: