First slide

Change in internal energy

Question

A thermodynamical process is shown in with $P_{A}$ = 3 X 10⁴ Pa; $V_{A}$ = 2 X 10^-3 m³; $P_{B}$ = 8 x 10⁴ N/m²; $V_{D}$ = 5 x 10^-3 m³.In the processes AB and BC, 600 J and 200 J of heat is added to the system respectively. The change in internal energy of the system in process AC would be:

Moderate

A

560 J
B

800 J
C

600 J
D

640 J

Solution

$P_{B}$ For process $A \to B \to C; Q = W + ∆ U \Rightarrow ∆ U = Q - W = 600 + 200 - (8 \times 10^{4}) (5 - 2) \times 10^{- 3} = 800 - 240 = 560 J$

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