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Three moles of a monoatomic gas are mixed with two moles a diatomic gas. When ‘Q’ amount of heat is supplied to the mixture at constant volume, temperature of the mixture is increased by 300C. Then ‘Q’ is equal to

a
55R
b
200R
c
325R
d
285R

detailed solution

Correct option is D

For the mixture, Cv = 3×3R2+2×5R23+2 = 1910R∴ Q = 3+2×19R10×30   Joule           = 285 R

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