The transverse displacement of a string clamped at its both ends is given by y(x,t)=0.06sin⁡2π3xcos⁡(120πt) where x and y are in m and t in s. The length of the string is 1.5 m and its mass is 3×10−2kg. The tension in the string is

The given equation isy(x,t)=0.06sin⁡2π3xcos⁡(120πt)Compare it with y(x,t)=2asin⁡kxcos⁡ωtwe get, k=2π3,  or  2πλ=2π3  or  λ=3mand ω=120π or 2πv=120π or v=60Hz=60s−1Velocity of wave, v=vλ=60s−1(3m)=180ms−1Mass per unit length of the string,μ=3×10−2kg1.5m=2×10−2kgm−1Velocity of transverse wave in the string, v=Tμ or v2=Tμ or T=v2μT=180ms−122×10−2kgm−1=648N