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Q.

Two identical containers joined by a small narrow pipe initially contain the same gas at pressure p0 and absolute temperature T0. One container is now maintained at the same temperature while the other is heated to 2T0. The common pressure of the gases will be

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a

32p0

b

43p0

c

53p0

d

2p0

answer is B.

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Detailed Solution

(n1+n2)i = (n1+n2)f                    p0VRT0+p0VRT0=pVRT0+pV2RT0∴                                p = (4/3)p0
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