Questions
Two identical containers joined by a small narrow pipe initially contain the same gas at pressure p0 and absolute temperature T0. One container is now maintained at the same temperature while the other is heated to 2T0. The common pressure of the gases will be
detailed solution
Correct option is B
(n1+n2)i = (n1+n2)f p0VRT0+p0VRT0=pVRT0+pV2RT0∴ p = (4/3)p0Talk to our academic expert!
Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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