Download the app

Questions  

Two identical vessels contain the same gas at pressures P1 and P2 at absolute temperatures T1 and T2, respectively. On joining the vessels with a small tube as shown in the figure, the gas reaches a common temperature T and a common pressure P. Determine the ratio PT.

 

a
[P1T1+P2T2T1T2]
b
12[P1T1+P2T22T1T2]
c
12[P1T2+P2T1T1T2]
d
[P1T2+P2T1T1T2]

detailed solution

Correct option is C

On combining the two vessels the total number of moles remains constant, i.e., n = n1+n2Using gas equation, we can write, n1 = P1VRT1; n2 = P2VRT2 and n = P(2V)RTwhere V is the volume of each vessel.Thus P(2V)RT = P1VRT1+P2VRT2or PT = 12[P1T1+P2T2]

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

For one-mole ideal gas, a process follows the relation P=V2V2+V02P0, where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?


phone icon
whats app icon