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Two perfect gases at absolute temperature T1 and T2 are mixed. There is no loss of energy. Find the temperature of the mixture if the masses of the molecules are mm1 and m2 and the number of molecules in the gases n1 and n2. Then final temperature of the mixture is 

a
n1T1+n2T22
b
n1T2+n2T1n1+n2
c
n1T1+n2T2n1+n2
d
T1+T22

detailed solution

Correct option is C

energy  of each molecule at temperature T is  E=32kTas energy is conserved n1E1+n2E2=n1+n2En132kT1+n232kT2=n1+n232kTT=n1T1+n2T2n1+n2

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