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Law of equipartition of energy
Question

Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at a temperature To, while box B contains one mole of helium at temperature (7/3) T0. The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature (Ignore the heat capacity of boxes). Then the final temperature of the gases, Tf, in terms of T0 is :

Moderate
Solution

Let final temperature be Tf then
Tf=n1C V1T1+n2CV2T2n1CV1+n2CV2=(1)52R(T0)+(1)32R73T0(1)52R+(1)32R=32T0

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