First slide

Variation of g

Question

The value of acceleration due to gravity on the surface of earth is x. At alttitude of ‘h’ from the surface of earth, its value is y. If ‘R’ is the radius of earth, then the value of h is

Easy

A

$\large \left ( \sqrt {\frac {x}{y}}-1 \right )R$
B

$\large \left ( \sqrt {\frac {y}{x}}-1 \right )R$
C

$\large \sqrt {\frac {y}{x}}R$
D

$\large \sqrt {\frac {x}{y}}R$

Solution

$\large {g}'=\frac {g}{\left ( 1+\frac hR \right )^2}$
$\large y=\frac {x}{\left ( 1+\frac hR \right )^2}\Rightarrow1+\frac hR$
$\large \Rightarrow \sqrt {\frac{x}{y}} \Rightarrow \frac{h}{R} = \sqrt {\frac{x}{y}} - 1$
$\large h = \left( {\sqrt {\frac{x}{y}} - 1} \right)R$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App