The weight of an object in the coal mine, sea level and at the top of the mountain are respectively $$W1$$, $$W2$$ and $$W3$$, then

Question

Infinity Learn · Accepted Answer

g at certain depth is $$g1$$ $$=$$ $$g(1$$ $$-d/R)Weight$$ in mine is $$w1$$ $$=$$ $$mg1$$ $$=$$ $$mg(1-d/R)weight$$ at sea level $$w2$$ $$=$$ mg    $$($$ acceleration due to gravity is the  gravity at sea $$level)$$ g at certain height is $$g11$$ $$=$$ $$GM/(R+h)2$$                                  $$g11$$ $$=$$ $$gR2/(R+h)2$$                                    $$g11$$ $$=$$ $$g(1-2h/R)weight$$ at mountain is $$w3$$ $$=$$ $$mg11$$ $$=$$ $$mg(1-2h/R)w1$$ < $$w2$$ > $$w3$$

The weight of an object in the coal mine, sea level and at the top of the mountain are respectively W₁, W₂ and W₃, then

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The weight of an object in the coal mine, sea level and at the top of the mountain are respectively W1, W2 and W3, then

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The weight of an object in the coal mine, sea level and at the top of the mountain are respectively W₁, W₂ and W₃, then