The weight of an object in the coal mine, sea level and at the top of the mountain are respectively W1, W2 and W3, then
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a
W1 < W2 > W3
b
W1 = W2 = W3
c
W1 < W2 < W3
d
W1 > W2 > W3
answer is A.
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Detailed Solution
g at certain depth is g1 = g(1 -d/R)Weight in mine is w1 = mg1 = mg(1-d/R)weight at sea level w2 = mg ( acceleration due to gravity is the gravity at sea level) g at certain height is g11 = GM/(R+h)2 g11 = gR2/(R+h)2 g11 = g(1-2h/R)weight at mountain is w3 = mg11 = mg(1-2h/R)w1 < w2 > w3