Questions
A vessel contains 1 mole of O2 (molar mass 32) at a temperature T. The pressure of the gas is P. An identical vessel containing 1 mole of He gas (molar mass 4) at a temperature 2T has a pressure of
detailed solution
Correct option is C
It is given that P1=P V2=V μ1=1 T2=2T T1=T μ2=1 V1=V P2=? We know thatPV=μRT P1 V1=μ1RT P2V2=μ2RT2 Dividing Eq.(1) by Eq. (2), We getP1V1P2V2=μ1RT1μ2RT2 PP2xVV=1xT1x2T⇒P2=2PTalk to our academic expert!
Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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