A vessel contains 1 mole of O2 (molar mass 32) at a temperature T. The pressure of the gas is P. An identical vessel containing 1 mole of He gas (molar mass 4) at a temperature 2T has a pressure of

It is given that P1=P      V2=V μ1=1        T2=2T T1=T        μ2=1 V1=V        P2=?   We know thatPV=μRT P1 V1=μ1RT P2V2=μ2RT2  Dividing Eq.(1) by Eq. (2), We getP1V1P2V2=μ1RT1μ2RT2 PP2xVV=1xT1x2T⇒P2=2P