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Q.

The work of 146 kJ is performed in order to compress one kilomole of a gas adiabatically and in this process the temperature of the gas increases by 7°C. The gas isR=8⋅3 J mol−1K−1

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An Intiative by Sri Chaitanya

a

diatomic

b

triatomic

c

monoatomic

d

mixture of monoatomic and diatomic

answer is A.

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Detailed Solution

For adibatic process, dQ = 0 i.e., dU = -dW∴ nCVdT=146×103JIf the the degrees of freedom, thennfR2×7=146×103 ∴ 103×f×8⋅3×72=146×103Solving, we get f=5⋅02≈5So, the gas is diatomic,

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