Consider the following reaction for the given image.

 

 

 

The product formed in the reaction is :

Reaction Steps:

Step 1: Oxymercuration

• The reagent Hg(OAc)₂  reacts with the double bond of the cyclic alkene, forming a mercurinium ion intermediate.
• A water molecule attacks the more substituted carbon (following Markovnikov's rule), resulting in the addition of a hydroxyl group (-OH) to the more substituted carbon.

Step 2: Demercuration

• The reagent NaBH₄  reduces the organomercury intermediate, replacing the mercury group with a hydrogen atom.

Final Product:

The product is a 1,2-diol, meaning the molecule contains two hydroxyl groups (-OH) on adjacent carbons. The reaction follows anti-stereoselectivity, so the hydroxyl groups are added to opposite faces of the ring.

Detailed Product Structure:

• The double bond in the original compound is converted into a single bond.
• One hydroxyl group (-OH) remains at its original position (tertiary -OH).
• A new hydroxyl group (-OH) is added to the carbon adjacent to the original -OH group.

Product: