Consider the following reaction for the given image

 

 

 

 

 

 

 The product (B) formed in the reaction is :

Reaction Analysis and Explanation:

Step 1: Reaction Description

• The starting compound (A) undergoes ozonolysis (O₃/Zn) followed by treatment with concentrated KOH.
• This leads to the formation of the compound shown on the right side, which contains:
  • An alcohol group (-OH).
  • A formate ion (HCO₂⁻).

Step 2: Reaction with HBr in CCl₄

• When the product reacts with HBr in CCl₄, the major product is determined by Markovnikov's rule:
  • Markovnikov's rule states that the hydrogen atom (H⁺) from HBr will attach to the carbon with the higher number of hydrogen atoms.
  • Bromine (Br⁻) attaches to the more substituted carbon (i.e., the carbon with fewer hydrogen atoms).

Major Product (B):

• Bromine will replace the -OH group, leading to the formation of a bromoalkane.