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(0, 0), (20, 15), (36, 15) are the vertices of a triangle then the ex-centre opposite to vertex (0, 0) is

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(35, 20)

(19, 18)

(16, 25)

(14, 22)

answer is A.

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Detailed Solution

$I_{1} = (\frac{- a x_{1} + b x_{2} + c x_{3}}{- a + b + c}, \frac{- a y_{1} + b y_{2} + c y_{3}}{- a + b + c}) = (35, 20)$

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