0.01 mole of iodoform reacts with Ag powder to produce a gas whose volume at NTP is

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224ml

112ml

336ml

1120 ml

answer is B.

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Detailed Solution

$large CH{I_3} + 6Ag + {I_3}CH xrightarrow{Delta } 6AgI + CH equiv CH$

(or)

$large mathop {2CH{I_3}}limits_{begin{array}{*{20}{c}} {2moles} \ {0.01mole} end{array}} + 6Agxrightarrow{Delta }mathop {CH equiv CH}limits_{begin{array}{*{20}{c}} {22,400ml} \ {'X'ml} end{array}} + 6AgI$

$large X = 22400 times frac{0.01}{2}$

X = 112ml

Volume of acetylene gas liberated at STP = 112ml

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