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Q.

0.05 moles of ${NaHCO}_{3}$ will react with how many equivalents of $Mg {(OH)}_{2}$ ?

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a

0.2 equivalent

b

0.05 equivalent

c

0.02 equivalent

d

0.01 equivalent

answer is B.

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Detailed Solution

Eq. of ${NaHCO}_{3}$ = Eq. of $Mg {(OH)}_{2}$

0.05 x1= eq. of $Mg {(OH)}_{2}$

$∴ Equivalents of Mg {(OH)}_{2} = 0.05$

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0.05 moles of NaHCO3 will react with how many equivalents of MgOH2 ?