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Q.

0.15 gm of an organic compound on combustion gave 0.44 gm of  CO2 and 0.27gm of  H2O. The molecular formula of organic compound can be 

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a

C4H8

b

C2H6

c

C2H2

d

C2H4

answer is B.

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Detailed Solution

% of C=1244×0.440.15×100

=80 
% of H=218×0.270.15×100 
= 20
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E.F. =  CH3
M.F=C2H6 

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