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0.16 grams of an organic compound when heated with ${Na}_{2} O_{2}$ followed by the addition of ${BaCl}_{2}$ solution gave 0.233 g of ${BaSO}_{4}$ . Percentage of sulphur in the organic compound is (Molecular weight of ${BaSO}_{4} = 233$ )

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25%

15%

20%

10 %

answer is D.

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Detailed Solution

$% of S = \frac{32}{233} \times \frac{W_{{BaSO}_{4}}}{W_{OC}} ×100$

$= \frac{32}{223} \times \frac{0.233}{0.16} \times 100$

= 20 %

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