0.2 mole sample of hydrocarbon $C_{x} H_{y}$ yields after complete combustion with excess $O_{2}$ gas, 0.8 mole of ${CO}_{2}, 1.0 mole of H_{2} O .$ Hence hydrocarbon is

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$C_{4} H_{10}$

$C_{4} H_{8}$

$C_{4} H_{5}$

$C_{8} H_{16}$

answer is A.

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Detailed Solution

$C_{x} H_{y} + O_{2} \overset{}{\to} {xCO}_{2} + \frac{y}{2} H_{2} O_{} 0.2 0 0.2 x \frac{y}{2} \times 0.2 given 0.2 x = 0 . 8 x = 4 0.1 y = 1.0 y = 10 ∴ C_{4} H_{10}$

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