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Q.

0π/2cos3xsinx  +cosxdx=

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a

π -12

b

π +14

c

π -14

d

π -34

answer is C.

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Detailed Solution

I = 0π/2cos3xsin x  + cosx dx_______(1)

use 0af(x) dx=  0af(a-x)  dx

I = 0π/2sin3xcosx + sin xdx_______(2)

Add (1) and (2)

2I = 0π/2cos3x  + sin3xsinx  + cosxdx

2I = 0π/2(1-sinx  cosx)  dx

2I = (x  +  14  cos  2x)0π2

2I = (π2-14)-(0+14)

2I = π2- 12

I = π-14

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