0.32 g of metal, gave on treatment with an acid, 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metal

$\text{ Equivalent weight }=\frac{\text{ Mass of metal }\times 11200}{\text{ Volume }\left(\text{in }\mathrm{mL}\right)\text{ of hydrogen }}$
Given, mass of metal = 0.32 g
volume of hydrogen at NTP = 112 mL
$\text{ Equivalent weight }=\frac{0.32\times 11200}{112}=32$