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0.365 gms of an organic compound containing nitrogen gave 56ml of nitrogen at STP. The % of nitrogen is___________

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answer is 19.

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Detailed Solution

Mole of $N = \frac{56}{22, 400}$
Mass of nitrogen in sample $= 28 \times \frac{56}{22400} = 0.07 g$
$% of N = 0.07 \times \frac{100}{0.365} = 19.18$

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