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0.45g of an organic compound containing carbon, hydrogen and oxygen on complete combustion gave 0.44g. of $C O_{2}$ and 0.09g. of $H_{2} O$ . The percentage of oxygen by weight in that compound is

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89.5

83.23

78.45

71.12

answer is D.

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Detailed Solution

$% C = \frac{12}{44} \times \frac{W t o f C O_{2}}{W t_{O . C}} \times 100 = 26.66$

$% H = \frac{2}{18} \times \frac{W t o f H_{2} O}{W t_{O . C}} \times 100 = 2.22$

$% O = 100 - (% C + % H) = 71.12$

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