0.01M CH3COOH is 4.24% ionised. What will be the percentage ionisation of 0.1 M CH3COOH.

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

0.01M $C H_{3} C O O H$ is 4.24% ionised. What will be the percentage ionisation of 0.1 M $C H_{3} C O O H$ .

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 1.34.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$K_{a} = C α^{2}$

$α = \sqrt{\frac{K_{a}}{C}}$

But the $K_{a}$ value will be the same as it is for the same acid i.e $C H_{3} C O O H$ .

$\frac{α_{1}}{α_{2}} = \sqrt{\frac{C_{2}}{C_{1}}}$

$α_{1} 4.24$ = $\frac{0.01}{0.1}$

$α_{2}$ = $\frac{0.316}{4.24}$ = 1.34

Hence, the answer is 1.34.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE