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Q.

0.05 moles of ${AlCl}_{3}$ is required to coagulate 500 ml of ${As}_{2} S_{3}$ sol. If its coagulation value is 10^xfind x

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answer is 2.

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Detailed Solution

$\begin{array}{l} 500 ⟶ 0 .05 moles \\ 1000 ⟶ ? \\ 0 .1 mole = 100 milli moles = 10^{2} \end{array}$

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