0.0833 mole of carbohydrate of empirical formula ${\mathrm{CH}}_2\mathrm{O}$ contain, I g of hydrogen. The molecular formula of the carbohydrate is

$\because$0.0833 moles of carbohydrate have hydrogen = I g

$\therefore 1\text{ mole of carbohydrate has hydrogen }=\frac{1}{0.0833}=12 \mathrm{g}$

$\text{ Given, empirical formula of carbohydrate }\left({\mathrm{CH}}_2\mathrm{O}\right)\text{ has }2 \mathrm{g}$ $\text{ of hydrogen, }\mathrm{n}=\frac{12}{2}=6$

$\therefore \text{ Molecular formula of carbohydrate is }{\left({\mathrm{CH}}_2\mathrm{O}\right)}_{\mathrm{n}}$$=\left({\mathrm{CH}}_2\mathrm{O}\right)\times 6={\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6$