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0.1g of an organic compound produced 0.0479 of AgBr in carius method. The per centage of Br in the compound is

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40%

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20%

answer is B.

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Detailed Solution

$A g B r - - - - - - - - B r 188 g - - - - - - - 80 0.0479 - - - - - x g m o f B r x = 0.0203 g p e r c e n t o f B r = \frac{0.0203}{0.1} \times 100 = 20$

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