0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of N₂ evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is____.[nearest integer]
(Given: Molar mass of $N_{2}$ is $28 {mol}^{- 1}$ . Molar volume of $N_{2}$ at STP : $22.4 L$ )

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answer is 14.

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Detailed Solution

$weight of organic compound = 0.2 g mass of N_{2} (g) evolved = \frac{22.4 \times 10^{- 3}}{22.4} \times 28 \begin{aligned} = 28 \times 10^{- 3} g \\ % of N = \frac{28 \times 10^{- 3}}{0.2} \times 100 = 14 \end{aligned}$

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