Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

020π(|sinx|+|cosx|)2dx is equal to :-

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

10(π+4)

b

10(π+2)

c

20π+2

d

20(π2)

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

I=020π(|sinx|+|cosx|)2dx;( Jack property) period of |sinx|+|cosx|=π2I=400π/2(sinx+cosx)2dxI=400π/2(1+sin2x)dxI=40x-cos2x20π2I=20(π+2)

Watch 3-min video & get full concept clarity

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
∫020π (|sin⁡x|+|cos⁡x|)2dx is equal to :-