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Q.

020π(|sinx|+|cosx|)2dx is equal to :-

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a

10(π+4)

b

10(π+2)

c

20(π2)

d

20π+2

answer is D.

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Detailed Solution

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I=020π(|sinx|+|cosx|)2dx;( Jack property) period of |sinx|+|cosx|=π2I=400π/2(sinx+cosx)2dxI=400π/2(1+sin2x)dxI=40x-cos2x20π2I=20(π+2)

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