0.216g of an organic compound gave 28.8 $c m^{3}$ of moist nitrogen measured at 288K and 732.7mm pressure. The percentage of nitrogen in the substance is approximately 3x. Then the
value of x is ___ (Aq. Tension at 288K = 12.7mm)

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answer is D.

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Detailed Solution

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{720 \times 28.8}{288} = \frac{76 \times V_{2}}{273}$

$V_{2} = \frac{72 \times 273}{760}$

$= 25.8$

$% o f N = \frac{28}{22400} \times \frac{28.8 \times 100}{0.216}$

$= 14.93 %$

$= 15 % (a p p r o x i m a t e l y)$

$3 x = 15 x = 5$

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