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0.2429 g sample of potassium is heated in oxygen 0.440 g of a crystalline compound is obtained. What is the formula of this compound?

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$K_{2} O$

${KO}_{2}$

${KO}_{3}$

answer is C.

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Detailed Solution

Mass of K= 0.242 g, rmss of compound = 0.440 g ,

mass of O = 0.440-0.242 = 0.198 g

$Relative molar ratio of K = \frac{0.242}{39} = 0.0006,$

$Relative molar ratio of O = \frac{0.198}{16} = 0.012$

Simple ratio of K = 1

Simple ratio of O = 2

So, the formula is ${KO}_{2}$ .

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