0.25 g of an organic compound containing chlorine gave 0.40 g of silver chloride in Carius estimation. The percentage of chlorine present in the compound is [in nearest integer] (Given: Molar mass of Ag is 108 g mol^-1 and that of Cl is 35.5 g mol^-1 )

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Detailed Solution

wt. of organic compound $= 0.25 g$
mass of $Cl = \frac{35.5}{143.5} \times 0.4 g$
$mass % of Cl in the organic compound = \frac{mass of Cl}{mass of org . comp .} \times 100 = \frac{35.5 \times 0.4}{143.5 \times 0.25} \times 100 = 39.58 %$

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