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Q.

0.28 g an organic compound in Dumas method liberated 22.4 ml of nitrogen at STP. The percentage of nitrogen in the compound is

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a

50

b

20

c

10

d

80

answer is B.

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Detailed Solution

 % of N=VN2(mL) at STP 8× wt.of org compound ωorganic compound =0.289% of N=22.48×0.28=10

 

 

 

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