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0.2g of an organic compound of Kjeldahls analysis gave ammonia enough, to just neutralize $20 c m^{3} o f 0.1 N H_{2} S O_{4}$ . The percentage of nitrogen in the compound is 2x. Then the value of x is ____

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answer is B.

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Detailed Solution

$% N = 1.4 \times n o o f m e q o f H_{2} S O_{4}$

$\frac{n e u t r a l i s e d t o N H_{3}}{M a s s o f O . C} \times 100$

$= \frac{1.4 \times 2}{0.2}$

$2 x = 14 x = 7$

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