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Q.

0.303g of an organic compound was analysed for nitrogen by Kjeldahl`s method. The ammonia gas evolved was absorbed in 50ml of 0.05M $H_{2} S O_{4}$ . The excess acid required 25ml of 0.1M $N a O H$ for neutralization. The percentage of nitrogen in the given compound is

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a

11.5

b

23

c

12.5

d

14.5

answer is A.

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Detailed Solution

$N o . o f e q o f H_{2} S O_{4} u l t i l i s e d f o r n e u t r a l i s a t i o n s = 5 - 2.5 = 2.5 m . e q . ∴ N o . o f m . e q . o f N {H_{3}}_{} l i b e r a t e d = 2.5 m . q . % o f N = N o . o f m e q . o f N H 3 \times 1.4 \div w t . o f O C = 2.5 \times 1.40 \div 0.303 = 11.55 % .$

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